Swift 2.0 notification flags fail when combined using the | operator

Swift 2 changed many of the types commonly used this way to implement the OptionSetType protocol instead. Consequently they support a syntax resembling arrays, so your particular example can be written like this.

  let notificationOptions = UIUserNotificationSettings(forTypes: [.Alert, .Badge], categories: nil)
  UIApplication.sharedApplication().registerUserNotificationSettings(notificationOptions)

Relatedly, checking whether an option belongs to an option set no longer requires a bitwise AND followed by testing for nil. Instead, ask whether that set contains the particular value, much as you would check an array for an element.

  let notificationOptions = UIUserNotificationSettings(forTypes: [.Alert, .Badge], categories: nil)

  if notificationOptions.types.contains(.Alert) {
      // handle this option
  }

For Swift 3, write those examples this way:

  let notificationOptions = UIUserNotificationSettings(types: [.alert, .badge], categories: nil)
  UIApplication.shared.registerUserNotificationSettings(notificationOptions)

and

  let notificationOptions = UIUserNotificationSettings(types: [.alert, .badge], categories: nil)

  if notificationOptions.types.contains(.alert) {
      // handle this option
  }

This is another possible expression:

  let notificationOptions = UIUserNotificationType.Alert.union(UIUserNotificationType.Badge)

This version worked for me

  //Successful version
  var notificationOptions = UIUserNotificationSettings(forTypes: UIUserNotificationType([.Alert, .Badge, .Sound]), categories: nil)

Swift 3 changed the syntax here.

          let notificationOptions = UIUserNotificationSettings(types: [.alert, .badge, .sound], categories: nil)
          UIApplication.shared.registerUserNotificationSettings(notificationOptions)