Converting integer arrays into C strings

I'm attempting to turn some integer array elements into a C string. HEre is an example of what I'm doing:

int digits[] = {2,4,3,0};
char text[6];
for (int pos=0; pos<4; ++pos) {
    text[pos]=digits[pos];
}
printf("%s",text);

Instead I see heart shapes or smiling faces, and I don't understand the reason.

The conversation continues 2

Follow the reasoning

tinbox14 Aug Permalink
For character output, printf uses that number's ASCII character (https://www.rapidtables.com/code/text/ascii-table.html).

The values 2, 4, 3, 0 correspond to STX, EOT, ETX, which aren't printable characters.

For instance, use 67, 68 instead to get letters.

Lio14 Aug

Your displayed program cannot produce output because it fails to compile.

It's unclear what you're trying to accomplsih, but consider this example:

int main(void) {
    int digits[] = {2, 4, 3, 0};
    char text[sizeof(digits) / sizeof(digits[0]) + 1] = {0,};
    char pieces[sizeof(digits) / sizeof(digits[0])][12];
    for (int pos = 0; pos < 4; pos ++ ) {
        text[pos] = digits[pos] % 10 + '0';
        snprintf(pieces[pos], 12, "%d", digits[pos]);
    }
    printf("%s\n", text);
    for (int pos = 0; pos < 4; pos ++ ) {
        printf("%s\n", pieces[pos]);
    }
}

Converting integer arrays into C strings

The conversation continues 2

Other sides of the same question

Escaping percent characters when calling String.Format?

Formatting strings with F#

Extracting one section of a tcl string